Take a break from those perplexing ancestors and try your hand at this cute little logic puzzle submitted by Dan Lynch
. Thanks to all of the similar logic puzzles I did growing up it only took me about 10 minutes, but even if it takes you several hours (while watching Law & Order) like Dan, it is a fun diversion from your genealogy brick walls.
[p][i]On June 1st, five couples who live in Trumbull will celebrate their wedding anniversaries. Their surnames are Johnstone, Parker, Watson, Graves and Shearer. The husbands' given names are Russell, Douglas, Charles, Peter and Everett. The wives' given names are Elaine, Joyce, Marcia, Elizabeth and Mildred. Keep in mind that no two couples have been married the same number of years. From the clues, determine the husband and wife that make up each couple and the number of years they have been married.
- Joyce has not been married as long as Charles or the Parkers, but longer than Douglas or the Johnstones.
- Elizabeth has been married twice as long as the Watsons, but only half as long as Russell.
- The Shearers have been married ten years longer than Peter and ten years less than Marcia.
- Douglas and Mildred have been married for 25 years less than the Graves who, having been married for 30 years, are the couple who have been married the longest.
- Neither Elaine or the Johnstones have been married the shortest amount of time.
- Everett has been married for 25 years
You can view the entire puzzle plus a Logic Grid to help you solve it at www.genealogyworldwide.com.
Can you solve it? How long did it take? Share your success or failure by clicking comments below.